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x^2+5=9x
We move all terms to the left:
x^2+5-(9x)=0
a = 1; b = -9; c = +5;
Δ = b2-4ac
Δ = -92-4·1·5
Δ = 61
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{61}}{2*1}=\frac{9-\sqrt{61}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{61}}{2*1}=\frac{9+\sqrt{61}}{2} $
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